![]() ![]() Hear constructive interference cause these are overlapping peak to peak, valley to valley perfectly. The same note next to it, if I played it like this I'd In other words if I took another speaker and I played Takes the same amount of time for both of these to go through a cycle, that means they have the same period, so if I overlap these, Period as the first wave, right so I'll put these peak to peak so you can see, compare the peaks, yep. Let's just say this wave has the exact same You overlap two waves, if I take another wave and So why am I telling you this? Well because we know if So in other words this entire graph is just personalizedįor that point in space, three meters away from this speaker. A minuscule amount but some amount, and if we graphed that displacement as a function of time ![]() The sound wave comes by and that causes this air to get displaced. Here, the air's chillin, just relaxin and then Just so we have a number to refer to, so there's air over Let's just say we're three meters to the right of this speaker. Point, one point in space, we measure what theÄisplacement of the air is as a function of time. Sound would sound like, and let's say it's sending this sound out and at a particular They're tuning instruments and whatnot so that's this Tone and so it would sound something like this. Speaker and it was playing a nice simple harmonic ![]() So this is gonna give you the displacement of the air molecules for any What's up everybody? I wanna talk to you about beat frequency, and to do so let me talk to you about this air displacement ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |